Steam required by a coil calculator
Steam required by a coil
Divide the useful heating load by usable enthalpy drop and coil efficiency.
Units
m˙=ηcoil×(hin−hout)qwater
m˙=ηcoil×(hin−hout)3600×qwater
Calculator
Enter the values you know and leave one box empty. Calculate finds the empty one, the result or any input.
Worked example
Given
- qwater = 240,000 Btu/h
- ηcoil = 0.88 —
- hin = 1,180 Btu/lb
- hout = 170 Btu/lb
m˙=0.88×(1180−170)240,000≈270
Given
- qwater = 120 kW
- ηcoil = 0.9 —
- hin = 2,800 kJ/kg
- hout = 420 kJ/kg
m˙=0.9×(2800−420)3600×120≈201.7
Symbols and units
| Symbol | Meaning | Unit |
| m˙ | required steam mass flow | lb/h |
| qwater | useful water-heating rate | Btu/h |
| ηcoil | coil heat-transfer efficiency | — |
| hin | steam inlet enthalpy | Btu/lb |
| hout | actual outlet-condensate enthalpy | Btu/lb |
| Symbol | Meaning | Unit |
| m˙ | required steam mass flow | kg/h |
| qwater | useful water-heating rate | kW |
| ηcoil | coil heat-transfer efficiency | — |
| hin | steam inlet enthalpy | kJ/kg |
| hout | actual outlet-condensate enthalpy | kJ/kg |
Results are estimates for study and screening. Check the inputs, units and assumptions before you use them for design, billing or contract decisions.